x-y=3;(x)/(3)+(y)/(2)=6

The value of x and y from the equation x-y=3 and (x)/(3)+(y)/(2)=6 are

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

(6)/(x+y)=(7)/(x-y)+3(1)/(2(x+y))=(1)/(3(x-y))

If (x+3)/(4)=5 and (y-2)/(3)=6 then x and y are:

(x-4)(x-3)=(x-6)(x-5) (y-9)(y-3)= (y-4)(y-3)

Simplify: (x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))

Simplify : (x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)