log(2x+3)(6x^(2)+28x+21)=4-60

Number of values of x satisfying the equation.log_(3x+7)(9+12x+4x^(2))+log_(2x+3)(6x^(2)+23x+21)=4 is

Solve: (log)_((2x+3))(6x^(2)+23x+21)+(log)_((3x+7))(4x^(2)+12x+9)=

The value of x satisfying log_((2x+3)) (6x^2+23x+21)=4-log_((3x+7)) (4x^2+12x+9) is

The number of solutions of the equation log_((2x + 3)) ( 6x^(2) + 23 x + 21) + log_((3x + 7)) (4x^(2) + 12 x + 9) = 4 is

21x^(2) - 28x + 10=0

21x^(2) - 28x + 10=0

21x^(2) - 28x + 10=0