sqrt(x)+y=11,quad x+sqrt(y)=7

sqrt(x)+y=11,x+sqrt(y)=7

If 0

(sqrt(x)+sqrt(y))^(2)=x+y+2sqrt(xy) and sqrt(x)sqrt(y)=sqrt(xy) , where x and y are positive real numbers . If x=2sqrt(5)+sqrt(3) and y=2sqrt(5)-sqrt(3) , then x^(4)+y^(4) =

If 0 (a) sqrt(x)-\ sqrt(y)=\ sqrt(x-y) (b) sqrt(x)+\ sqrt(x)=\ sqrt(2x) (c) xsqrt(y)=ysqrt(x) (d) sqrt(x y)=\ sqrt(x)\ sqrt(y)

sqrt(x)+y=7,x+sqrt(y)=11

x sqrt(x)+y sqrt(y)=a sqrt(a) then find (dy)/(dx)

Find the angles between the pairs of straight line x-y sqrt(3)=5 and sqrt(3)x+y=7

Solve using the method of substitution. ( i) 2x-3y =7,5x +y=9 (ii) 1.5x+ 0.1 y =6.2,3x -0.4y=11.2 (iii) 10% of x +20% of y =24, 3x-y=20 (iv) sqrt2x -sqrt 3y =1, sqrt 3x -sqrt 8y =0

sqrt x + y = 7 x+ sqrty = 11

sqrt x+ y =7 and sqrt y +x=11