[2x+1y-3=0],[2x-31,-7=0]

Solve the following system of equations graphically: 2x+y-3=0;\ \ \ 2x-3y-7=0

If [[x+y,x-2],[2x-z,0]]=[[2,5],[3,1]] then the values of x,y,z.

2x+3y-5=0,2x+3y+15=0,x+y-7=0,x+y+7=0 are sides of a parallelogram.Then the centre of the parallelogram is

Solve the following equations by Elimination method : 3x+2y-11/3=0 , -7x+5y-31/3=0

Transform 12x^(2)+7xy-12y^(2)-17x-31y-7=0 to rectangular through the point (1, -1) inclined at an angle tan^(-1)((4)/(3)) to the original axes.

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then: