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Aluminium forms [AIF(6)]^(3-) ion but bo...

Aluminium forms `[AIF_(6)]^(3-)` ion but boron does not form `[BF_(6)]^(3-)` ion. Explain.

A

The atomic size of B is small

B

Of absence of d-orbital in B atom

C

Of high I.P B-atom

D

B is non -metal

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Explain the following (a) Gallium has higher ionisation enthalpy than aluminium (b) Boron does not exist as B^(3+) ion (c) Aluminium forms [AlF_(6)]^(3-) ion but boron does not form [BF_(6)]^(3-) ion.

Explain the following : (a) Boron has high melting and boiling points. (b) The p pi - p pi back bonding occurs in the halides of boron and not in those of aluminimum. ( c) Boron and aluminium halides behave as Lewis acids. (d) Aluminium forms [AlF_(6)]^(3-) ion, but boron does not form [BF_(6)]^(3-) ion.

Boron is unable to form BF_(6)^(3-) – ion. Explain.

Why boron does not form B^(3+) ion?

Assertion: Al forms [AIF_(6)]^(3-) but B does not from [BF_(6)]^(3-) Reason: BF_(3) on hydrolysis gives HBF_(4) .

NARAYNA-13TH GROUP ELEMENTS-Comphensive Type Question
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