2-Methyl propene on treatment with acidic potassium permanganate gives

Options

A. Propanal, `CO_(2)`
B. Propanone, `CO_(2)`
C. Propanoic acid, `CO_(2)`
D. Butanone, `CO_(2)`

Answer

To solve the question regarding the reaction of 2-methylpropene with acidic potassium permanganate, we will follow these steps:

### Step 1: Identify the Structure of 2-Methylpropene
2-Methylpropene, also known as isobutylene, has the molecular formula C4H8. Its structure can be represented as follows:

```
CH3
|
CH2=C-CH3
```

### Step 2: Understand the Reaction with Acidic Potassium Permanganate
Potassium permanganate (KMnO4) is a strong oxidizing agent. When it reacts with alkenes in an acidic medium, it typically leads to oxidative cleavage of the double bond, resulting in the formation of carbonyl compounds.

### Step 3: Predict the Products of the Reaction
In the case of 2-methylpropene, the double bond (C=C) will be oxidized. The reaction with acidic potassium permanganate will lead to the formation of two products due to the cleavage of the double bond:

1. Acetone (CH3COCH3)
2. Acetic acid (CH3COOH)

### Step 4: Write the Balanced Reaction
The balanced reaction can be represented as follows:

\[ \text{C}_4\text{H}_8 + \text{KMnO}_4 \xrightarrow{\text{H}^+} \text{CH}_3\text{COCH}_3 + \text{CH}_3\text{COOH} + \text{Mn}^{2+} + \text{K}^+ + \text{H}_2\text{O} \]

### Final Answer
The treatment of 2-methylpropene with acidic potassium permanganate gives acetone and acetic acid.

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