Incorrect Statement

Options

A. `SnCl_(2)` reduces Nitrobenzene to aniline
B. `SnCl_(2)` reduces gold chloride `(AuCl_(3))` to metallic gold sol ( purple of cassius)
C. When `SnCl_(2)` is treated with excess of `NaOH` an insoluble `Sn(OH)_(2)` which precipitate is formed.
D. When `SnCl_(2)` reacts with conc. `HCL,` chlorostannic acid `H_(2)SnCl_(6)` is formed.

Answer

C

Explanation

`SnCl_(2)+NaOHrarrSn(OH)_(2)darr`
`SnCl_(2)+underset(("excess"))(NaOH)rarrNa_(2)SnO_(2)("soluble")`