|[del x,e+x,b+2],[e+x,x,a+x],[b+x,a+x,x]|=0

If f(x)=|[a,-1, 0],[a x, a,-1],[a x^2,a x, a]|,t h e nf(2x)-f(x) is divisible by (a) a (b) b (c) c ,d ,e (d) none of these

If A=[[x, x] , [x, x]] and B=[[x, -x] , [-x, x]] then prove that x e^A=1/2(A.e^(2x)+B) where e^A= I+A+A^2/(2!)+...

Let f(x)={(e^x-1+ax)/x^2, x>0 and b, x=0 and sin(x/2)/x , x<0 , then

If a >0 and discriminant of a x^2+2b x+c is negative, then =a b a x+bb c b x+c a x+bb x+c0 is +v e b. (a c-b)^2(a x^2+2b x+c) c. -v e d. 0

int(x-1)\ e^(-x)\ dx is equal to x e^x+C (b) x e^x+C (c) -x e^(-x)+C (d) x e^(-x)+C

Suppose f(x)=e^(a x)+e^(b x) , where a!=b , and that f^(prime_ prime)(x)-2f^(prime)(x)-15f(x)=0 for all xdot Then the value of (|a b|)/3 is ___

Suppose f(x)=e^(a x)+e^(b x) , where a!=b , and that f prime prime(x)-2f^(prime)(x)-15f(x)=0 for all xdot Then the value of (|a b|)/3 is ___

Suppose f(x)=e^(a x)+e^(b x) , where a!=b , and that f''(x)-2f^(prime)(x)-15f(x)=0 for all xdot Then the value of (|a b|)/3 is ___

Let A={(x,y): y= e^x , x in R } , B={(x,y): y= e^(-x) , x in R } . Then :

Let A={(x, y)|y=e^(x), x in R} and B={(x, y)|=e^(-x), x in R} . Then