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1000(1+r/(1,200))^(12) The expression ...

`1000(1+r/(1,200))^(12)`
The expression above gives the amount of money, in dollars, generated in a year by a $1,000 deposit in a bank account that pays an annual interest rate of r %, compounded monthly. Which of the following expressions shows how much additional money is generated at an interest rate of 5% than at an interest rate of 3% ?

A

`1,000(1+(5-3)/(1,200))^(12)`

B

`1,000(1+(5/3)/(1,200))^(12)`

C

`(1,000(1+5/(1,200))^(12))/(1,000(1+3/(1,200))^(12))`

D

`1,000(1+5/(1,200))^(12)-1,000(1+3/(1,200))^(12)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the additional money generated by a $1,000 deposit at two different interest rates: 5% and 3%, compounded monthly. ### Step-by-Step Solution: 1. **Identify the formula for compound interest:** The formula for the amount \( A \) generated by a principal \( P \) at an interest rate \( r \) compounded monthly for one year is given by: \[ A = P \left(1 + \frac{r}{1200}\right)^{12} \] Here, \( P = 1000 \). 2. **Calculate the amount generated at 5% interest:** Substitute \( r = 5 \) into the formula: \[ A_{5\%} = 1000 \left(1 + \frac{5}{1200}\right)^{12} \] Simplifying the expression inside the parentheses: \[ A_{5\%} = 1000 \left(1 + \frac{1}{240}\right)^{12} \] 3. **Calculate the amount generated at 3% interest:** Substitute \( r = 3 \) into the formula: \[ A_{3\%} = 1000 \left(1 + \frac{3}{1200}\right)^{12} \] Simplifying the expression inside the parentheses: \[ A_{3\%} = 1000 \left(1 + \frac{1}{400}\right)^{12} \] 4. **Find the additional money generated:** The additional money generated at 5% compared to 3% is given by: \[ \text{Additional Money} = A_{5\%} - A_{3\%} \] Substituting the expressions we found: \[ \text{Additional Money} = 1000 \left(1 + \frac{5}{1200}\right)^{12} - 1000 \left(1 + \frac{3}{1200}\right)^{12} \] Factoring out the common term: \[ \text{Additional Money} = 1000 \left(\left(1 + \frac{5}{1200}\right)^{12} - \left(1 + \frac{3}{1200}\right)^{12}\right) \] 5. **Final Expression:** The final expression that shows how much additional money is generated at an interest rate of 5% compared to 3% is: \[ 1000 \left(\left(1 + \frac{5}{1200}\right)^{12} - \left(1 + \frac{3}{1200}\right)^{12}\right) \]

To solve the problem, we need to calculate the additional money generated by a $1,000 deposit at two different interest rates: 5% and 3%, compounded monthly. ### Step-by-Step Solution: 1. **Identify the formula for compound interest:** The formula for the amount \( A \) generated by a principal \( P \) at an interest rate \( r \) compounded monthly for one year is given by: \[ A = P \left(1 + \frac{r}{1200}\right)^{12} ...
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