`I=(P)/(4pi r^(2))`
At a large distance r from a radio antenna, the intensity of the radio signal I is related to the power of the signal P by the formula above.
For the same signal emitted by a radio antenna, Observer A measures its intensity to be 16 times the intensity measured by Observer B. The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?

Options

A. `(1)/(4)`
B. `(1)/(16)`
C. `(1)/(64)`
D. `(1)/(256)`

Explanation

To solve the problem, we start with the formula for intensity:

\[ I = \frac{P}{4\pi r^2} \]

where \(I\) is the intensity, \(P\) is the power of the signal, and \(r\) is the distance from the antenna.

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