An element hobbyist is building a radio which reequires `150 Omega` in her circuit, but she has only `220Omega, 79 Omega and 92 Omega` resistors available. How can she connect the available resistor to get desired value of resistance ?

Explanation

Given : Requirement of resistors `=150 Omega`
Available resistors `R_(1)= 220Omega, R_(2)=79 Omega`
`R_(3)=92 Omega`
Solution

`(I)/(R_(P))=(1)/(R_(I))+(1)/(R_(2))=(1)/(220)+(1)/(79)=(220+79)/(17380)=(299)/(17380)`
`R_(S)=R_(P)+R_(3)`
`=58+92`
`R_(S)=150 Omega`
The required resistors is obtained by parallel combination of `220 Omega and 79 Omega` in series with `92Omega`.