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Calculate the currents in the following ...

Calculate the currents in the following circuit.

Text Solution

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From Kirchoff s I law at junction B
`I_(1)-I_(2)-I_(3)=0 `
`I_(3)=I_(1)-I_(2) " "...(1)`
Applying Kirchoff's II in A B E F A
`100 I_(3)+100 I_(1)=15`
`100(I_(1)-I_(2))+100 I_(1)=15`
`200I_(1)-100I_(2)=15 " "...(2)`
Apply II law to B C D E D
`-100I_(2)+100 I_(3)=9 [ :. I_(3)=I_(1-I_(2)]`
`-100 I_(2)+100 I_(3) =9`
`-200I_(2)+ 100 I_(1)=9 " "...(3)xx2`
`-400I_(2)=200 I_(1)=18 " "...(4)`
From (2)- `100 I_(2)+200 IO_(1)=15 " "...(2)`
`(4)+(2)-300 I_(2)=3`
`I_(2)=(3)/(-300)=-0.01A`
`I_(2)=0.01A`
Sub. `I_(2)` in (2)
`200 I_(2)-100xx0.01=15`
`200 I_(1)-I=15`
`I_(1)=(16)/(200)-0.08A`
Sub, `I_(1) and I_(2)` in equation (1)
`I_(3)=I_(1)-I_(2)=0.07-(-0.01)`
`I_(3)=0.08`
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