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The emf of a battey is 3 volts and inte...

The emf of a battey is 3 volts and internal resistance `0.125Omega`. The difference of potential at the terminal of battey when connected across an external resistance of `1Omega` is

A

`1.67V`

B

`0.67V`

C

`2.67V`

D

`3.67V`

Text Solution

Verified by Experts

The correct Answer is:
C
`r=0.125 Omega, R=1`
`epsi=3V.V=?`
`r=((epsi-V)R)/(V) rArr Vr = xi R-VR`
`Vr+VR=epsiR`
`V(r+R)= epsi`
`V=(epsiR)/(r+R)`
`V=(3xx1)/(1+0.125)=(3)/(1.125)=2.67V`
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