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Five 3Omega resistances are arranged in ...

Five `3Omega` resistances are arranged in a polygen (5 sides). What is the resistance between any two corners ?

A

`2.4Omega`

B

`3Omega`

C

`9Omega`

D

`5Omega`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/(R_(P))=(1)/(3)+(1)/(12)+(1)/(12)=(4+1)/(12)=(5)/(12)`
`R_(p)=(12)/(5)=2.4 Omega`
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