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How any 160 Omega resistor in parallel a...

How any `160 Omega` resistor in parallel are required to carry a current of 5 A on a 100 V line ?

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(p)=(V)/(1)=(100)/(I)=(100)/(5)= 20 Omega`
Also, `R_(p)=(R)/(n)`
`20=(R)/(n) rArr n=(R)/(20)=(160)/(20)`
`:. n=8`
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