A silver wire has a resistance of `2.1 Omega 27.5^(@)C Omega` and a resistance of `2.7Omega "at" 100^(@)C`. Determinethe temperature co-efficient of resistance of the silver.

Explanation

Given `t_(1)=27.5^(@)C,t_(2)=100^(@)C`
`R_(1)=R_(27.5)=2.1Omega`
`R_(2)=R_(100)=2.7`
Temperature co-efficient of resistane.
`(RA)/(l)=(5xx6xx10^(-7))/(15)=(R_(2)-R_(2))/(R(t_(2)-t_(1)))=((2.72.1))/(2.1(100-27.5))`
`=0.0039^(@)C^(-1)`