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Using Kichhoff's law in the given circui...

Using Kichhoff's law in the given circuit determine the current 'I' in the are EF.

Text Solution

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Applying kirchoff's first rule at E
`rArr 0.5 =I_(1)=I`
Where 'I' flows through 'R'
Now Kirchoff's 2dn rule in closed loop FEABF
`-2I_(2)=0.5xx2=-4+3`
`-2I_(2)+1=-1`
`cancel-2I_(2)=cancel-2`
The Current in arm `EF=12=+1A`
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