Home
Class 12
PHYSICS
Angle of dip at a place, wher horizontal...

Angle of dip at a place, wher horizontal and verical componet of earth's fiedl are qual is

A

`45^(@)`

B

`60^(@)`

C

`30^(@)`

D

`0^(@)`

Text Solution

Verified by Experts

The correct Answer is:
a
`tan I = B_(V)/(B_(H))" "[:' B_(V) = B_(H)\]`
`tan I = B_(V)/B_(V) = 1 rArr I = tan^(-1)(1) `
` rArr I = 45^(@)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The angle of dip at a place where horizontal and vertical components of earth's magnetic field a equal is

The horizontal component of earth's magnetic field at a place is 3.6 xx 10^(-5) T. if the angle of dip at this place is 60^(@) , the vertical components of earth's field at this place is

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^(@) . What is the value of horizontal component of the earth's magnetic field at equator ?

At a certain location in Africa, a compass 12^@ west of the geographic north. The northe tip of the magnetic needle of a dip circle in the plane of magnetic meridian points 60^@ above the horizontal . The horizontal component of the earth's field measured to be 0.16 G. Specify the direction and magnitude of the earth's field at the location.

In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is 0.26 G and the dip angle is 60^@ . What is the magnetic field of the earth at this location ?

At a certain place the horizontl component of earth's magnetic field is sqrt(3) times vertical component. The angle of dip at that place is

The horizontal component and vertical components of Earth's maganetic field at a plase are 0.15 G and 0.26 G respectively. Calculate the angle of dip and resultant magnetic field.