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An electron of mass 0.90 xx 10^(-30) kg ...

An electron of mass `0.90 xx 10^(-30)` kg under the action of a magnetic field moves in a circle of 2.0 cm radius at a speed `3.0 xx 10^6 ms^-1`. If a proton of mass `1.8 xx 10^(-27) kg` was to move in a circle of the same radius in the same magnetic field, then its speed will be

A

`3.0 xx 10^(6) m//s`

B

`1.5 xx 10^(3) m//s`

C

`6.0 xx 104 m//s`

D

cannot be estimated from the same data

Text Solution

Verified by Experts

The correct Answer is:
b
`Bqv ' = (mv^(2))/r rArr Bqr = m V`
for electrons and protons, B, q, r same
` :. Mv ` = a constant
` m_(e) V_(e) = m_(p) v_(p) `
`v_(p) = (m_(e) V_(e))/ m_(p) `
` v_(p) = (0.90 xx 10^(-30) xx 3 xx 10)/(1. 8 xx 10^(-27))`
` v_(p) = 1.5 xx 10^(3) m//s `
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Knowledge Check

  • An electron of mass 9xx10^(-31) kg revolves in a circle of radius 0.53 Å around the nucleus of hydrogen atom with a velocity of 2.2xx10^(6) "ms"^(-1) . What is the angular momentum of the electron ?

    A
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    B
    `(3h)/(3pi)`
    C
    `(h)/(pi)`
    D
    `(h)/(3pi)`

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