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According to Ampere's circuital law...

According to Ampere's circuital law

A

`oint vecB.vec(dl) = mu_(0) I_(0)`

B

`oint vecu . vec(dl) = B * I_(0) `

C

`oint " " vec(mu_(0)) * vecB = I_(0) dl `

D

`oint" " vec(I_(0)). vec(dl) = mu_(0) B `

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The correct Answer is:
a
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