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In Ampere's circuital law, the value of ...

In Ampere's circuital law, the value of line integral `oint vecB . dl`

A

depends on share of the current path

B

depends on the position of the wire within the magnetic field

C

depends on the direction of the current

D

is zero , when the closed path does not encricle the wire

Text Solution

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The correct Answer is:
d
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Knowledge Check

  • Ampere's circuital law is another form of

    A
    Tangent law
    B
    Biot - Savart law
    C
    Ampere's Swimming rule
    D
    End rule

  • According to Ampere's circuital law

    A
    `oint vecB.vec(dl) = mu_(0) I_(0)`
    B
    `oint vecu . vec(dl) = B * I_(0) `
    C
    `oint " " vec(mu_(0)) * vecB = I_(0) dl `
    D
    `oint" " vec(I_(0)). vec(dl) = mu_(0) B `

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