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An alpha - particle enters a magnetic fi...

An `alpha` - particle enters a magnetic field of 1 T with a velocity `10^(6)` m/s in a direction perpendicular to the field . The force on `alpha` - particle is ________ .

A

`1.6 xx 10^(-13)` N

B

`6.4 xx 10^(-13) N`

C

`4.8 xx 10^(-13)N`

D

`3.2 xx 10^(-13) N`

Text Solution

Verified by Experts

The correct Answer is:
d
`F = B qv sin theta , (q = 2e)`
` = 1 xx (2 xx 1.6 xx 10^(-19)) xx 10^(6) xx sin 90^(@)`
` = 3.2 xx 10^(-13) N`
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