A short bar magnet o magnetic field . It experiences a torque of `0.05` J.
Calculate the magnitude of the magnetic field.

Explanation

Magnetic moment ` mu = 0.6 ` J/T
Angle of inclination with magnetic field `theta = 30^(@)`
Torque acts on bar magnet `tau = 0.05 ` J
Magnitude of magnetic field B = ?
`tau = vecmu xx vec B = mu B sin theta `
`B = tau/(mu sin theta) = (0.051)/ (0.6 xx sin 30^(@))`
` = (0.051)/(0.6 xx 1/2) = (2 xx 0.051)/(0.6) = (0.102)/ (0.6) `
`B = 0.17 T`