Home
Class 12
PHYSICS
A magnetic needle is free to rotate in a...

A magnetic needle is free to rotate in a vertical plans parallel to the magnetic meridian has its north tip down at `60^(@)` with horizontal . The horizontal component of the earth's magnetic field at the place is known to be `0.4 xx 10^(-4)` T determine the magnitude of earth's magnetic field at the place.

Text Solution

Verified by Experts

Angle of dip `theta = 60^(@)`
`H = 0.4 xx 10^(-4) T`
If `B_(e)` is the earth's magnetic field , then
`H = B_(e) cos theta`
` B_(e) = H/(cos theta) = (0.4 xx 10^(-4)T)/(cos 60^(@))`
` = 0.8 xx 10^(-14)` T
Promotional Banner

Similar Questions

Explore conceptually related problems

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22^@ with the horizontal . The horizontal component of the earth's magnetic field at the place is known to be 0.35 G . Determine the magnitude of the earth's magnetic field at the place.

What is meant by horizontal component of Earth's magnetic field.

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

Write the value of vertical component of Earth's magnetic field.

The angle of dip at a place where horizontal and vertical components of earth's magnetic field a equal is

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^(@) . What is the value of horizontal component of the earth's magnetic field at equator ?

The horizontal component of earth's magnetic field at a place is 3.6 xx 10^(-5) T. if the angle of dip at this place is 60^(@) , the vertical components of earth's field at this place is

At a certain location in Africa, a compass 12^@ west of the geographic north. The northe tip of the magnetic needle of a dip circle in the plane of magnetic meridian points 60^@ above the horizontal . The horizontal component of the earth's field measured to be 0.16 G. Specify the direction and magnitude of the earth's field at the location.

How can we resolve the earth's magnetic field at a place into two rectangular components ?