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The length of a solenoid is 0.2m and it ...

The length of a solenoid is `0.2`m and it has 120 turns. Find the magnetic field in its interior if a current of `2.5` A is flowing through it .

Text Solution

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`l = 0.2 `m
` N = 120, I = 25 A`
Magnetic field in the interior of the solenoid ,
`B = mu_(0)nI = mu_(0)(N/l) I `
` = 4 pi xx 10^(-7) xx (120 xx 2.5)/(0.2)`
` = 1.85 xx 10^(-3) T`
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