Home
Class 12
PHYSICS
Calculate the torque of a 100 turns rect...

Calculate the torque of a 100 turns rectangular coil of length 40 cm and breadth 20 cm, carrying a current of 10 A , when placed making an angle of `60^(@)` with a magnetic field of 57.

Text Solution

Verified by Experts

`I = 10A, N = 100, 1 = 40` cm
` b = 20 cm, B = 5 T, theta = 60^(@)`
` A = l xx b = 40 xx 20 = 800 cm^(2) = 8 xx 10^(-2) m^(2)`
Torque , `tau = NBIA sin theta `
` = 100 xx 5 xx 10 xx 8 xx 10^(-2) xx sin 60^(@)`
` = 346.41 ` Nm
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the magnetic field B at the centre of a rectangular loop of length l and width b, carrying a current i.

The magnetic induction at the center of a circular coil having 5 turn and radius 2 pi cm carrying a current of 500 mA is

Consider a tightly wound 100 turn coil of radius 10 cm, carrying a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil?

Magnetic flux density at the center of a circular coil of diameter 20 cm carrying a current 5 A kept in air is

A circular coil of radius 2.0 cm has 500 turns in it and carries a current of 1.0 A . Its axis makes an angel of 30^@ with the uniform magnetic field of 0f magnitude 0.40 T that exists in the space. Find the torque acting on the total.

A circular coil of radius 5 cm and has 50 turns carries a current of 3 ampere. The magnetic dipole moment of the coil is

Consider a 10cm long protion of a straight wire carrying a current of 10 A placed in a magnetic field of 0.1 T making an angle of 53^@ with the wire. What magnetic force does the wire experience?

A cirular coil of wire cansiting of 100 turns ,each of readius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field barB at the centre of the coil ?