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A galvanometer of resistance 15 Omega gi...

A galvanometer of resistance `15 Omega` gives full scale deflection for a current of 2mA. Calculate the shunt resistance needed to convert it into an ammeter of range 0 to 5A.

Text Solution

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`G = 15 Omega,I_9g) = 2 mA = 2 xx 10^(-3) A`
` I = 5A`
Shunt resistance , `S = (I_(g)G)/(I-I_(g))`
` = (2 xx 10^(-3) xx 15)/(5 - 2 xx 10^(-3))`
` = 0.006 Omega`
The resistance `S = 0.006 Omega` is connected in parallel with the galvanometer in order to decrease the resistance of the galvanometer .
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