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A closely wound coil of radius 0.02 m is...

A closely wound coil of radius 0.02 m is placed perpendicular to the magnetic field. When the magnetic field is change from 8000 T to 2000 T in 6 s, an emf of 44 V is induced. Calculate the number of turns in the coil.

Text Solution

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Given : Raduis of the closely wound conditional R = 0.02 m
`therefore" Area of the closely "A =pi^(2)=(22)/(7)xx0.02xx0.02m^(2)`
Change in magetic in magnetic field dB = 8000 - 2000 = 6000 T
Change in magnetic in time dt = 6s
To find :
No. of turns of the coil N = ?
`e=(d)/(dt)(NAB.costheta)" "[theta=0because"coil is "botr" to magnetic field "]`
Formula :
`e=NA.(dB)/(dt)`
`44=N.(22)/(7)xx0.02xx0.02xx(6000)/(6)`
`N=(cancel(44)xx7)/(cancel(4)xx10^(-4)xx10^(3)xx22)`
`=(cancel(11)xx7xxcancel10^(5))/(cancel(22)_(cancel(2)))=35`
N = 35 turns.
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