A rectangular coil of area `6cm^(2)` having 3500 turns is kept in a uniform magnetic field of 0.4 T. Initially, the plane of the coil is perpendicular to the field and is then rotated through an angle of `180^(@).` If the amount of charge flowing through the coil is............when resistance is `35Omega`

Explanation

Given : Area of rectangular coil
`=6cm^(2)=6xx10^(-4)m^(2)`
No. of turns N = 3500
Magnetic field B =0.4 T
Resistance of the coil R `=35Omega`
Change in flus `Phi_(2)-Phi_(1)`
`=NABcos180^(@)-NABcos0^(@)`
Solution :
e = -NAB - NAB
e = -2 NAB
`e=-2xx3500xx6xx10^(-4)xx0.4`
`e=16.8xx103xx10-4`
`e=168xx10^(-2)`
Current flowing through coil `I(e)/(R)`
`I(168xx10^(-2))/(35)=4.8xx10^(-2)`
`48xx10^(-3)C`