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Determine the self-inductance of 4000 tu...

Determine the self-inductance of 4000 turn air-core solenoid of length 2m and diatmeter 0.04 m.

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Given : No. of turns of air -cor solenoid N = 4000
Length of air-core solenoid L = 2 m
Diameter of air - core solenoid D = 0.04 m
Radius of air - core solenoid `r=(0.04)/(2)=0.02m`
Area of air - core solenoid `A=pi^(2)`
`=3.14xx.02xx.02m^(2)`
To find :
Self inductance L = ?
`L=mun^(2)Al" "" Where "mu-mu_(0)mu_(r)`
`mu_(r)=1" for air core, "mu_(0)=4pixx10^(-7)`
`n=(N)/(l)`
Solution :
`L=mu_(0)(N^(2))/(l^(2))A.l`
`L=4pixx10^(-7)xx(4000xx4000)/(2)xx3.14xx.02xx.02`
`=12.62xx10^(-3)`
`L=12.62xx10^(-3)`
`L=12.62mH.`
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