A coil of 200 turns carries a current of 4 A. If the magnetic flux through the coil is `6xx10^(-5)`Wb, find the magnetic energy stored in the medium surrounding the coil.

Explanation

Given : No. of turns of coil N = 200
Current passing through coil I = 4A
Magnetic flux through coil`Phi=6xx10^(-5)Wb`
To find :
Magnetic energy stored in the medium surrounding the coil `=(1)/(2)LI^(2)`
Self inductance L `=(NPhi)/(I)`
Solultion :
`therefore" energy"U_(B)" "=(1)/(2).NPhi.I`
`=(1)/(2)xx200xx6xx10^(-5)xx4`
`=24xx10^(-3)`
`U_(B)=0.024J.`