Calculate the instantaneous value at 60o, average value and RMS value of an alternating current whose peak value is 20 A.

Explanation

Given : `I_(m)=20A`
Angle `theta=60^(@).`
To find :
i. i=I_(m)sin`omega`t(or)i=I_(m)sin`theta`(instantaneous value of AC)
ii. `I_(av)(2I_(m))/(pi)["Average value of AC"]`
iii. `I_(RMS)=0.707I_(m)(or)(I_(m))/(sqrt(2))`
Solution :
i. `i=I_(m)sintheta=20xxsin60`
`=20xx(sqrt(3))/(2)=10sqrt(3)`
= 17.32 A
ii. `I_(av)=(2xx20)/((22)/(7))=(40xx7)/(22)=(280)/(22)=12.727A.`
iii. `I_(RMS)=0.707xx20=14.14A.`