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The current flowing through an inductor ...

The current flowing through an inductor of self inductance L is continuously increasing plot a graph showing the variation of
induced emf versus `(dI)/(dt)`

Text Solution

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Induce emf versus `(dI)/(dt)e=-L(dI)/(dt)`
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Knowledge Check

  • A current of 1 A flowing through a coil of inductance 1 henry is switched off in one milli second. Then the induced emf is:

    A
    `-100V`
    B
    `+100V`
    C
    `-1000V`
    D
    `-10000V`

  • When the current flowing through one coil changes from 11A to 5A during a time interval of 0.1 sec, an emf of 60 mv is induced in the neighbourhood coil. The mutual inductance of it will be:

    A
    0.1 H
    B
    0.01 H
    C
    0.001 H
    D
    0.002 H

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    An inductor of self inductance 12 H carries a steady current of 2A. How can a 60V self-induced e.m.f. be made to appear in the inductor?

    The current i flowing in a coil varies with time as shown in the figure. The variation of induced emf with time would be .......

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    A 50 Hz ac current of peak value 2 A flows through one of the pair of coils. If the mutual inductance between the pair of coils is 150 mH, then the peak value of voltage induced in the second coil is

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