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A light bulb is rated 100 W for 200 V AC...

A light bulb is rated 100 W for 200 V AC supply of 50 Hz. Calculate (i) resistance of the bulb (ii) the rms current through it.

Text Solution

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i. Given Power `P=VI" "(I=(V)/(R))`
`P=Vxx(V)/(R)`
Solution :
`R(V^(2))/(P)=((200)^(2))/(100)=400V`
ii. `E_(rms)=(E_(m))/(sqrt(2))`
`E_(rms)=E_(rms)xxsqrt(2)=200xxsqrt(2)`
`E_(rms)=282.84V`
`I_(rms)=(I_(m))/(sqrt(2))=(R)/(sqrt(2))=(282.84)/(565.6)`
`I_(rms)=0.50A.`
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