Write down the integral form of modified Ampere's circuital law.

Explanation

Maxwell modified Ampere's law as where I + `I_(c ) + I_(d)` which means the total current enclosed by the surface is sum of conduction current and displacement current. When a constant current is applied, displacement current `I_(d)` = 0 and hence `I_(c) + I`. Between the plates , the conduction current `I_(c )` = 0 hance `I_(d)` = I.
`oint vec(B).d vec(S) = mu_(0)I = mu_(0) (I_(c ) + I_(d))`