If the relative permeability and relative permitivitty of the medium is 1.0 and 2.25, respectively. Find the speed of the electromagnetic wave in this medium.

Explanation

The relative permeability of the medium `mu_(r )` = 1
The relative permittivity of the medium `epsilon_(r )` = 2.25
Speed of Electromagnetic wave in this medium v = ?
` v = (1)/(sqrt(mu epsilon))= (1)/(sqrt(mu_(0) mu_(r ) epsilon_(0)epsilon_(r ))`
`v = (1)/(sqrt(mu epsilon))cdot (1)/(sqrt(mu_(r ) epsilon_(r)))`
But `(1)/(sqrt(mu_(0)epsilon_(0)) = c ` (velocity of Electromagnetic wave in vacuum)
`therefore v = (c )/(sqrt(mu_(r ) . epsilon_(r ))) rArr v ^(2) = (c^(2))/(mu_(r )epsilon_(r))`
`v^(2) = (3 xx 10^(8) xx 3xx 10^(8))/(1 xx 2.25) = (9 xx 10^(16))/(2.25)`
`v^(2) = 4 xx 10^(16) m s^(-1)`
`therefore v = 2 xx 10^(8) m s^(-1)`