In an Electromagnetic wave propagating along X - direction , then magnetic field osciallates at a frequency . `5 xx 10^(8)` Hz and has an amplitude of `10^(-7)` tesla, acting along the Y- direction.
what is the wavelength of the wave?
(ii)write the expression representing the corresponding oscillating electric field.

Explanation

Given:
The frequency of Electromagnetic wave
`gamma = 5 xx 10^(8)`Hz
`lambda` = 0.6 m.
`lambda = (c )/(lambda) = (3 xx 10^(8))/(5 xx 10^(8))` = 0.6
the amplitude of magnetic field `B_(0) =10^(7)` T
To find:
The amplitude of electric field `E_(0) `= ?
`E_(0) =c B_(0) = 3 xx 10^(8) xx 10^(-7) = 30 `V `m^(-1)`
The expression for oscillating electric field `E_(z)`?
`E = E_(0) sin 2 pi (vt + (1)/(lambda)cdot x )`
`E = 30 . sin 2 pi (3 xx 10^(8) t + 1.66 x ) Vm^(-1)`