The magnetic field amplitude of an Electromagnetic wave is `1.6 xx 10^(-7)` T. if the frequency is 30 MHz. determine electric field. Angular velocity `omega ` and `lambda`.

Explanation

Given : the amplitude of magnetic field of an Electromagnetic wave B = `1.6 xx 10^(-7)` T
To find :
the amplitude of electric field of an electromganetic wave E = ?
frequency `lambda` = 30 MHz = 30 `xx 10^(6)` Hz.
to find : Angular velocity `omega ` = ?
Wavelength of electromagnetic wave `lambda` = ?
Ampere of electric field E = ?
`(E )/(B) = C rArr E C.B rArr 3 xx 10^(8) xx 1.6 10^(-7)`
E = 48 V `m^(-1)`.
(ii) Angular velocity , `omega = 2pi gamma `
`omega = 2 xx 3.14 xx 30 xx 10^(6)`
`omega = 1.885 xx 10^(8) "rad/s".`
(iii) Wavelength of Electromagnetic wave , `lambda = (C )/(gamma)`
` lambda = (3 xx 10^(8))/(30 xx 10^(6)) = 10`m
`lambda = 10`m.