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If the horizontal range of a projectile ...

If the horizontal range of a projectile is equal to the maximum height reached, then the corresponding angle of projection is ____ .

A

`tan ^(-1) 1`

B

`tan ^(-1) sqrt(3)`

C

`tan^(-1) 4`

D

`tan^(-1) 12`

Text Solution

Verified by Experts

The correct Answer is:
C
Horizontal Range = max. height reached
`(mu^(2) sin2theta)/(g)=(mu^(2)sin^(2)theta)/(2g)`
`2 sintheta cos theta= (sin^(2)theta)/(2)`
` 4 costheta= sintheta`
`tan theta implies theta = tan^(-1)4`
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