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The radioactive constant of radium is 4....

The radioactive constant of radium is `4.28 xx 10^(-4)` per year, its half period is approximately

A

2000 year

B

1240 year

C

1620 year

D

2440 year

Text Solution

Verified by Experts

The correct Answer is:
C
`T_(1//2)=(0.6931)/(lambda)=(0.6931)/(4.28xx10^(-4))`
= 1621 years `~~` 1620 years
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