Home
Class 12
PHYSICS
The acceleration of a particle performin...

The acceleration of a particle performing S.H.M. is 12 cm/`s^(2)` at a distance of 3 cm from the mean position. Its time period is _____ .

A

2 sec

B

4 sec

C

1.54 sec

D

3.14 sec

Text Solution

Verified by Experts

The correct Answer is:
D

In S.H.M `" " alpha = omega^(2)y`
`implies " " omega^(2) = (alpha)/(y) = (12)/(3) = 4 sec^(-2)`
`:. " "T= (2pi)/(omega)=(2pi)/(2) = pi= 3.14 sec`
Promotional Banner

Similar Questions

Explore conceptually related problems

A pendulum is hung in a very high building and is moving freely to and fro like a simple harmonic oscillator. If the acceleration of the bob is 16 ms^(-1) at a distance of 4 m from the mean position, then the time period is

A disc rotates about its axis with a constant angular acceleration of 4rad/s^2 . Find the radial and tangential acceleration of a particle at a distance of 1 cm from the axis at the end of the first second after the disc starts rotating.

Find the magnitude of the linear acceleration of a particle moving in a circle of radius 10 cm with uniform speed completing the circle in 4s.

A particle executing a SHM has maximum acceleration at a distance of 0.5 cm from its mean position is 2cm//s^(2) . What will be its velocity when it is at a distance of 1 cm from its mean position.

The maximum displacement of a particle executing SHM is 1 cm and the maximum acceleration is (1.57)^(2)cm//s^(2) . Its time period is……………..