Home
Class 12
PHYSICS
The amplitude of an oscillating simple p...

The amplitude of an oscillating simple pendulum is 10 cm and its period is 4 sec. It speed 1 second after it passes its equilibrium position is

A

Zero

B

0.157 m/s

C

0.212 m/s

D

0.32 m/s

Text Solution

Verified by Experts

The correct Answer is:
A

Velocity of simple pendulum
`v = a omegacosomegat = 10xx(2pi)/(T)cos""(2pi)/(T).1`
`=(20pi)/(4)cos""(2pi)/(4).1=0`
Promotional Banner

Similar Questions

Explore conceptually related problems

Suppose the amplitude of a simple pendulum having a bob of mass m is theta_0 . Find the tension in the string when the bob is at its extreme position.

A partical executes simple harmonic oscillation with an amplitude a. the period of oscillation is T The minimum time taken by the partical to travel half of the amplitude from the equilibrium position is:

A simple harmonic oscillator has amplitude A and time period T. Its maximum speed is………………

A seconds pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket:

The time -period of a simple pendulum is 2s and its can go to and fro from equilibrium position at a maximum distance of 5 cm. if at the start of the motion the pendulum is the position of maximum displacements towars the right of the equilibrium position, then write the displacement equation of the pendulum.

The kinetic energy of a particle, executing SHM, is 16 J when it is at its mean position. If the amplitude of oscillations is 25 cm, and the mass of the particle is 5.12 kg, the time period of its oscillation is………….

The angular velocity and the amplitude of a simple pendulum are omega and a, respectively. The ratio of its kinetic and potential energies at a displacement x from the mean position is……………

If the length of simple pendulum is tripled, what will its new time period is terms of original period T ?