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The amplitude of a particle in S.H.M. de...

The amplitude of a particle in S.H.M. decreases from 20 cm to 15 cm in 2 minutes. Its energy decreases by nearly _________ .

A

0.44

B

0.25

C

0.225

D

0.125

Text Solution

Verified by Experts

The correct Answer is:
A
`E= (1)/(2) m omega^(2)a^(2)`. Thus percentage change in energy is `(DeltaE)/( E) = (20^(2)-15^(2))/(20^(2))xx100=44%`
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