What change occurs when AgCl is doped with `CdCl_(2)` ?

Explanation

(a) When AgCl is doped with `CdCl_(2)`, two `Ag^(+)` ions will be replaced by one `Cd^(2+)` ion to maintain electrical neutrality.
(b) Thus, a hole is created at the lattice site for very `Cd^(2+)` ion introduced. Hence the crystal becomes conductor.