Diffraction angle `2 theta` equal to `14.8 ^(@)` for a crystal having interplanar distance in the crystal is 0.400 nm when second order diffraction was observed. Calculate the wavelength of X-ray used.

Explanation

Data `:`
Diffraction angle,
`2 theta = 14.8 ^(@) ` `:. Theta = 7.4^(@)`
Inter planar distance `, d = 0.400 nm`
Order of reflection, n = 2
Formula `:`
`n lambda = 2 d sin theta `
`:.` wavelength,
Solution `:`
`lambda = ( 2 d sin theta )/(2)`
`= d sin theta `
`= 0.400 sin 7.4 ^(@)`
`= 0.400 xx 0.1288 `nim
`= 0.0512 nm`
`lambda =0.0512 nm`