A metallic element exists as a cubic lattice. Each edge of the unit cell is `2.88Å`. The density of the metal is `7.20 gcm^(-3)`. How many unit cells there will be in 100g of the metal ?

Explanation

Volume of unit cell ` = ( 2.88Å) ^(3) = 23.9 xx 10^(-24) cm^(3) `
Volume of 100 g of the metal ` ( m )/( A ) = ( 100g)/( 7.2 gcm^(-3))`
Number of unit cells in this volume
` = ( 13.9 cm^(3))/( 23.9 xx 10^(-24)cm^(3))`
`= 5.82 xx 10^(23)`