The rate of formation of a dimer in a second order reaction is `7.5xx10^(-3)"mol L"^(-1)s^(-1)` at `0.05"mol L"^(-1)` monomer concentration. Calculate the rate constant.

Options

A. 0.15
B. 3
C. 0.3
D. 1.5

Answer

b

Explanation

For a second order reaction
`k = (R )/([A]^(2)) " "` …(1)
Where k = rate constant of reaction
R = rate of reaction
[A] = concentration of reactant or products
using equation
`k=(7.5xx10^(-3))/((0.05)^(2))=3.0 `