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A gas phase reaction has energy of activ...

A gas phase reaction has energy of activation `200 "kJ mol"^(-1)`. If the frequency factor of the reaction is `1.6xx10^(13)s^(-1)`. Calculate the rate constant at 600 K. `(e^(-40.09)=3.8xx10^(-18))`.

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`k=Ae^(-((Ea)/(RT)))`
`k=1.6xx10^(13)s^(-1)e^(-((200xx103"J mol"^(-1))/(8.314 JK^(-1)mol^(-1)xx600 K)))`
`k=1.6xx10^(13)s^(-1)e^((-40.1))`
`k=1.6xx10^(13)s^(-1)xx3.8xx10^(-18)`
`k=6.21xx10^(-5)s^(-1)`
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