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A first order reaction laws on rate cons...

A first order reaction laws on rate constant `1.15xx10^(-3)s^(-1)`. How long will 5 g of this reactant take to reduce to 3 g ?

Text Solution

Verified by Experts

`[R]_(0)=5g, [R]=3g`
`K=1.15xx10^(-3)s^(-1)`.
As the reaction is of first order
`K=(2.303)/(t)"log"([R]_(0))/([R])`
`t=(2.303)/(1.15xx10^(-3))"log"(5g)/(3g)`
`=200xx10^(3)(log 1.667)s`
`=20xx10^(3)xx0.22 19s`
`= 443.8 s`
= 444 s (appromximetly).
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