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Reaction is first order in A and second ...

Reaction is first order in A and second in B.
How is the rate affected when the concentrations of both A and B are doubled ?

Text Solution

Verified by Experts

When the concentration of both A and B are doubled.
`-(d[R])/(dt)=k[A][B]^(2)`
`= k[2A][2B]^(2)`
`=8.k [A] [B]^(2)`
Therefore, the rate of reaction will increase 8 times.
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